Given N_(2(g)) + 3H_(2(g)) to 2NH_(3(g)) , Delta_(r) H^( @) = -92.4 "kJ mol"^(-1) What is the standard enthalpy of formation of NH_(3) gas ?

Given N_(2(g)) + 3H_(2(g)) to 2NH_(3(g)) , Delta_(r) H^( @) = -92.4 "k

1.	Given N_(2(g)) + 3H_(2(g)) to 2NH_(3(g)) , Delta_(r) H^( @) = -92.4 "kJ mol"^(-1) What is the standard enthalpy of formation of NH_(3) gas ?
Answer» Solution :`(1)/(2) N_(2(g)) + (3)/(2)H_(2(g)) to NH_(3(g))` `therefore Delta_(f) H^( Theta ) = (-92.4)/( 2) = -46.2 "kJ/mol"`