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Given pH of a solution A is 3 and it is mixed with another solution B having pH 2. If both mixed then resultant pH of the solution will beA. 3.2B. 1.9C. 3.4D. 3.5

Answer» Correct Answer - B
pH of the solution A = 3
`[H^(+)]_(B) = 10^(-3)M`.
pH of the solution B = 2
`[H^(+)]_(B) = 10^(-2)M`
`[H^(+)]_(B) = 10^(-3) + 10^(-2) = 10^(-3) + 10 xx 10^(-3) = 11 xx 10^(-3)`.
`pH = -log(11 xx 10^(-3)) = 3 - log 11`
`= 3 - 1.04 = 1.95`.


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