1.

Given: Pt(s)"|"underset(1"bar")H_2(g)"|"0.1MNH_4OH(aq)"||"0.1MCH_3COOH(aq)"|"underset(1"bar")H_2(g)"|"Pt(s) pK_b(NH_4OH)=5, (CH_3COOH)=5,(2.303RT)/F=0.06 Volume of 0.1 m NH_4OH in anode half cell=100ML Volume of 0.1 M CH_3COOH in cathode half cell =100mL Which is /are correct statement?

Answer»

The EMF of given cell is 0.48V.
The emf of given cell is 0.36V when 50mL,0.1M NAOH added to cathode compartment
The emf of given cell is 0.36V when 50mL 0.1M HCl added to ANODE compartment
The emf of given cell is 0.192V when 100ML 0.1M NaOH added to anode compartment

Answer :A::B::C


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