Given standard `E^(c-):` `Fe^(3+)+3e^(-)rarrFe," "E^(c-)=-0.036` Fe^(2+)+2e^(-)rarr Fe," "E^(c-)=-0.440V` The `E^(c-)` of `Fe^(3+)+e^(-) rarr Fe^(2+) ` isA. `-0.476V`B. `-0.404V`C. `0.404V`D. `0.772V`

Given standard `E^(c-):` `Fe^(3+)+3e^(-)rarrFe," "E^(c-)=-0.036` Fe^(2

1.	Given standard `E^(c-):` `Fe^(3+)+3e^(-)rarrFe," "E^(c-)=-0.036` Fe^(2+)+2e^(-)rarr Fe," "E^(c-)=-0.440V` The `E^(c-)` of `Fe^(3+)+e^(-) rarr Fe^(2+) ` isA. `-0.476V`B. `-0.404V`C. `0.404V`D. `0.772V`
Answer» Correct Answer - d `Fe^(3+)+3e^(-) rarr Fe(E_(1))" "(i)` `Fe^(2+)+2e^(-) rarr Fe(E_(2))" "(ii)` Net equation `Fe^(3+)+e^(-) rarr Fe^(2+)(E_(3))" "(iii)` `[` Obtained by `Eqs. (i)-(ii)]` `E_(3)=(n_(1)E_(1)-N_(2)e_(2))/(n_(3))=(3(-0.036)-2(-0.0440))/(1)` `=0.772V`

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