Given standard electode potenitals ` Fe^(2+) + 2e^(-) rarr Fe, E^@ =- 0. 44 V ` ………………(1) ` Fe^(3+) + 2e^(-) rarr Fe, E^@ =- 0. 036 V` ………….(2) The standard electrode pptential `E^@ ` for `Fe^(2+) + e rarr Fe^(2+)` is.A. ` -0. 476 V`B. ` -0. 404 V`C. `0. 404 V`D. ` +0. 772 V`

Given standard electode potenitals ` Fe^(2+) + 2e^(-) rarr Fe, E^@ =-

1.	Given standard electode potenitals ` Fe^(2+) + 2e^(-) rarr Fe, E^@ =- 0. 44 V ` ………………(1) ` Fe^(3+) + 2e^(-) rarr Fe, E^@ =- 0. 036 V` ………….(2) The standard electrode pptential `E^@ ` for `Fe^(2+) + e rarr Fe^(2+)` is.A. ` -0. 476 V`B. ` -0. 404 V`C. `0. 404 V`D. ` +0. 772 V`
Answer» Correct Answer - D `Fe^(2+) + 2e rarr Fe, DeltaG_1^@ =- nE^2 F=- 2 F (-0.44)` `= 0.88 F` `Fe^(2+) + 2e rarr Fe, DeltaG_2^@ =- nE^2 F=- 2 F (-0.036)` ` =0.108 F` On subtracting (1) from (2) `Fe^(3+) +d^- rarr Fe^(2+)` or `Delta G =- 0. 772 F` or ` Delta G =- nE^@ F=- 0.772F` Or ` E^@ = (0.772 )/1 -.0772 V`.

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Given standard electode potenitals ` Fe^(2+) + 2e^(-) rarr Fe, E^@ =- 0. 44 V ` ………………(1) ` Fe^(3+) + 2e^(-) rarr Fe, E^@ =- 0. 036 V` ………….(2) The standard electrode pptential `E^@ ` for `Fe^(2+) + e rarr Fe^(2+)` is.A. ` -0. 476 V`B. ` -0. 404 V`C. `0. 404 V`D. ` +0. 772 V`

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