InterviewSolution
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InterviewSolution
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Given standard electrode potentials `K^(o+)|K=-2.93V, Ag^(o+)|Ag=0.80V`, `Hg^(2+)|Hg=0.79V``Mg^(2+)|Mg=-2.37V,Cr^(3)|Cr=-0.74V` Arrange these metals in their increasing order of reducing power. |
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Answer» It may be noted that lesser the `E^(@)` value for an electrode, more will be reducing power. The increasing order of reducing power is : `Ag^(+)//Ag lt H^(2+)//Hg lt Cr^(3+)//Cr lt Mg^(2+)//Mg lt K^(+)//K` |
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