1.

Given that \((1^2 + 2^2 + 3^2 + ...+10^2)=385\), the value of \((2^2 +4^2 +6^2 + ...+ 20^2)\) is equal to1. 7702. 11553. 15404. (385)2

Answer» Correct Answer - Option 3 : 1540

Given:

 \((1^2 + 2^2 + 3^2 + ...+10^2)=385\)

Calculation:

\(2^2(1^2 +2^2 +3^2 + ...+ 10^2)\)

⇒ 4 × 385 = 1540

∴ The value of \((2^2 +4^2 +6^2 + ...+ 20^2)\) is equal to 1540.

 

 

 



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