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Given that \((1^2 + 2^2 + 3^2 + ...+10^2)=385\), the value of \((2^2 +4^2 +6^2 + ...+ 20^2)\) is equal to1. 7702. 11553. 15404. (385)2 |
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Answer» Correct Answer - Option 3 : 1540 Given: \((1^2 + 2^2 + 3^2 + ...+10^2)=385\) Calculation: \(2^2(1^2 +2^2 +3^2 + ...+ 10^2)\) ⇒ 4 × 385 = 1540 ∴ The value of \((2^2 +4^2 +6^2 + ...+ 20^2)\) is equal to 1540.
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