Given that 10g of a dibasic acid (molarmass = 100) are present in 600

1.	Given that 10g of a dibasic acid (molarmass = 100) are present in 600 mL of the solution.The density of the solution is 1.02 g mL-1. Molalityof solution is(1) 0.17(2) 034(3) 0.99(4) 0.016
Answer» Given the volume of solution is = 600mland moles of solute is = 10/100 = 0.1 moles and density is given , so mass of solution = Vd = 6001.02 = 612gm so, mass of solvent = 612-10g = 602 assume solvent is water(d=1gm/ml) so, volume of water = 602/1 = 602ml therefore M = mol/L = 0.1/0.602 = 0.16 = 0.17M option 1

Given that 10g of a dibasic acid (molarmass = 100) are present in 600 mL of the solution.The density of the solution is 1.02 g mL-1. Molalityof solution is(1) 0.17(2) 034(3) 0.99(4) 0.016

Answer»

Given the volume of solution is = 600mland moles of solute is = 10/100 = 0.1 moles

and density is given , so mass of solution = V*d = 600*1.02 = 612gm

so, mass of solvent = 612-10g = 602

assume solvent is water(d=1gm/ml) so, volume of water = 602/1 = 602ml

therefore M = mol/L = 0.1/0.602 = 0.16 = 0.17M

option 1