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Given that 2 is a root of the equation `3x^2-p(x+1)=0` and that the equation `px^2-qx+9=0` has equal roots, find the values of p and q |
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Answer» 1)`3x^2-p(x+1)=0` x=2 is a root `3(2)^2-p(2+1)=0` `12-3p=0` `p=4` `px^2-qx+9=0` `4x^2-qx+9=0` `D=0` `b^2-4ac=0` `q^2=4*4*9` `q=2*2*3` `q=pm12`. |
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