Given that 2Cl−→Cl2+2e−,E∘=−1.36V; H2O→2H++12O2+2e−,E∘ – InterviewSolution

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1.	Given that 2Cl−→Cl2+2e−,E∘=−1.36V; H2O→2H++12O2+2e−,E∘=−1.23V. On electrolysing 1M NaCl solution with inert electrodes, which of the following is correct regarding liberation of electrolytic products ?
Answer» Given that $2 C l^{-} \to C l_{2} + 2 e^{-}, E^{\circ} = - 1.36 V;$ $H_{2} O \to 2 H^{+} + \frac{1}{2} O_{2} + 2 e^{-}, E^{\circ} = - 1.23 V .$ On electrolysing 1M NaCl solution with inert electrodes, which of the following is correct regarding liberation of electrolytic products ?

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