1.

Given that AOB is a straight line and O is the centre of the circle. Find the value of y.(a) 44° (b) 11° (c) 68° (d) 36°

Answer»

(c) 68°

∠BOC = 2 × ∠BAC = 2 × 22° = 44° 

(Angle at the centre = 2 × angle at any point on the remaining part of the circle)

∠AOC = 180° – ∠BOC = 180°– 44 = 136° (∵ AOB is a straight line)

\(\Rightarrow\) ∠ADC = \(\frac{1}{2}\) x ∠AOC = \(\frac{1}{2}\) x 136º = 68º 

(Angle at any pt. on the remaining part of the circle = \(\frac{1}{2}\) × angle at the centre)



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