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Given that AOB is a straight line and O is the centre of the circle. Find the value of y.(a) 44° (b) 11° (c) 68° (d) 36° |
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Answer» (c) 68° ∠BOC = 2 × ∠BAC = 2 × 22° = 44° (Angle at the centre = 2 × angle at any point on the remaining part of the circle) ∠AOC = 180° – ∠BOC = 180°– 44 = 136° (∵ AOB is a straight line) \(\Rightarrow\) ∠ADC = \(\frac{1}{2}\) x ∠AOC = \(\frac{1}{2}\) x 136º = 68º (Angle at any pt. on the remaining part of the circle = \(\frac{1}{2}\) × angle at the centre) |
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