1.

Given that C+ O_(2) to CO_(2)DeltaH^(@) = -x kJ 2CO+ O_(2) to 2CO_(2) DeltaH^(@) = -y kJ The enthalpy of formation of CO will be

Answer»

`y -2x`
`(2x -y)/(2)`
`(y - 2x)/(2)`
`2x -y`

Solution :(i) `C+ O_(2) to CO_(2)DELTAH = -x KJ`
(ii) `2CO+ O_(2) to 2CO_(2)DeltaH = -y kJ`
The REQUIRED equation is
`C + 1/2O_(2) to CODeltaH` = ?
Divinding eqn (ii) by 2
(iii) `CO+1/2O_(2) to CO_(2) DeltaH = -y/2 kJ`
SUBTRACT eqn (iii) from eqn (i)
`C + 1/2 O_(2) to CODeltaH - x + y/2`
or `= (y - 2x)/(2)`.


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