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Given that C+ O_(2) to CO_(2)DeltaH^(@) = -x kJ 2CO+ O_(2) to 2CO_(2) DeltaH^(@) = -y kJ The enthalpy of formation of CO will be |
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Answer» `y -2x` (ii) `2CO+ O_(2) to 2CO_(2)DeltaH = -y kJ` The REQUIRED equation is `C + 1/2O_(2) to CODeltaH` = ? Divinding eqn (ii) by 2 (iii) `CO+1/2O_(2) to CO_(2) DeltaH = -y/2 kJ` SUBTRACT eqn (iii) from eqn (i) `C + 1/2 O_(2) to CODeltaH - x + y/2` or `= (y - 2x)/(2)`. |
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