Given that `DeltaH_("comb")of C(s) , H_(2) (g) and CH_(4) (g) are , -394 , -294 and -829 kJ//mol` respectively. The heat of formation fo `CH_(4)` isA. `70 kJ//mol`B. ` -71. 8 kJ // mol`C. `-244 kJ//mol`D. `-748 kJ // mol `

Given that `DeltaH_("comb")of C(s) , H_(2) (g) and CH_(4) (g) are , -3

1.	Given that `DeltaH_("comb")of C(s) , H_(2) (g) and CH_(4) (g) are , -394 , -294 and -829 kJ//mol` respectively. The heat of formation fo `CH_(4)` isA. `70 kJ//mol`B. ` -71. 8 kJ // mol`C. `-244 kJ//mol`D. `-748 kJ // mol `
Answer» Correct Answer - a the formation of `CH_(4)` is represented as : `C(s)+2H_(2)(g)to CH_(4)(g),` ` DeltaH_(f)=(DeltaH_("comb"))_(R)-(DeltaH("comb")_(P)` ` =[-394+2 (-284)-(-892)kJ` `-962 + 892 =-70 kJ mol^(-1)`

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Given that `DeltaH_("comb")of C(s) , H_(2) (g) and CH_(4) (g) are , -394 , -294 and -829 kJ//mol` respectively. The heat of formation fo `CH_(4)` isA. `70 kJ//mol`B. ` -71. 8 kJ // mol`C. `-244 kJ//mol`D. `-748 kJ // mol `

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