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The specific heat at constant volume for a gas is 0.075 cal/g and at constant pressure it is 0.125 cal/g. Calculate, (i) the molecular weight of gas, (ii). Atomicity of gas. |
Answer» (i) `C_(P)-C_(V)=(R)/(M)` where, M=molecular of gas `0.125-0.075=(1.987)/(M)` `M=39.74~~40` (ii) `(C_(P))/(C_(V))=gamma` `therefore=(0.125)/(0.075)=1.66` `therefore` 1.66 value of `gamma` shows that the gas is monoatomic. |
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