Given that dipole moment of H_(2) Omolecule is 1.84 D, bond angle is 105^(@), O -H bond distance 0.94Å, cos 75Å = 0.2588,calculate the charge on oxygen atom in H_(2) Omolecule .

Given that dipole moment of H_(2) Omolecule is 1.84 D, bond angle is 1

1.	Given that dipole moment of H_(2) Omolecule is 1.84 D, bond angle is 105^(@), O -H bond distance 0.94Å, cos 75Å = 0.2588,calculate the charge on oxygen atom in H_(2) Omolecule .
Answer» Solution :`mu_(H_(2)O) = sqrt(mu_(O-H)^(2) + mu_(O-H)^(2)+ 2 mu_(OH)^(2)cos 105^(@))` `(1.84)^(2) = 2mu_(O-H)^(2) + 2mu_(O-H)^(2)XX(-0.2588)(because cos 105^(@) = cos (180^(@) - 75^(@)) = - cos 75^(@))` ` 3.3856 = mu_(O-H)^(2) (1 - 0.2588)` or` 1.4824 mu_(O-H)^(2)= 3.3856 or mu_(O-H) = 1.51 D` but` mu _(O-H) ` = charge `(delta) xx ` bond distance (d) ` therefore1.51 xx10^(-18)` esu cm = ` delta xx (-0.94 xx10^(-10) cm)` or ` delta = 1. 606 xx10^(-10)` esu As O-atom ACQUIRES charge = ` 2delta ` (one from each O-H bond) , THEREFORE , charge on O-atom ` =2xx 1.606 xx10^(-10) EQU = 3.212xx10^(-10) ` esu .