Given that `E^o` values of `Ag^+//Ag, K^+//K, Mg^(2+)//Mg` and `Cr^(3+) //Cr` are `0.08 V, -2 .93 V, -2 37 V` and ` -0. 74 V` respectively. Therefore the order for the reducing power of the metal is .A. `Ag gtCr gtMg gt K`B. `Ag gtCr gtMg gt K`C. `Ag gt Cr gt K gt Mg`D. `Cr gt Ag gt Mg gt K`

Given that `E^o` values of `Ag^+//Ag, K^+//K, Mg^(2+)//Mg` and `Cr^(3+

1.	Given that `E^o` values of `Ag^+//Ag, K^+//K, Mg^(2+)//Mg` and `Cr^(3+) //Cr` are `0.08 V, -2 .93 V, -2 37 V` and ` -0. 74 V` respectively. Therefore the order for the reducing power of the metal is .A. `Ag gtCr gtMg gt K`B. `Ag gtCr gtMg gt K`C. `Ag gt Cr gt K gt Mg`D. `Cr gt Ag gt Mg gt K`
Answer» Correct Answer - B More the negativ e `E^@` value , larger the reducing power of the metal.

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Given that `E^o` values of `Ag^+//Ag, K^+//K, Mg^(2+)//Mg` and `Cr^(3+) //Cr` are `0.08 V, -2 .93 V, -2 37 V` and ` -0. 74 V` respectively. Therefore the order for the reducing power of the metal is .A. `Ag gtCr gtMg gt K`B. `Ag gtCr gtMg gt K`C. `Ag gt Cr gt K gt Mg`D. `Cr gt Ag gt Mg gt K`

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