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Given that `E^o` values of `Ag^+//Ag, K^+//K, Mg^(2+)//Mg` and `Cr^(3+) //Cr` are `0.08 V, -2 .93 V, -2 37 V` and ` -0. 74 V` respectively. Therefore the order for the reducing power of the metal is .A. ` Ag gt Cr gt Mg gt K`B. ` Ag lt Cr lt Mg lt K`C. ` Ag gt Cr gt K gt Mg`D. ` Cr gt Ag gt Mg gt K` |
Answer» Correct Answer - B The greater the standard reduction potential, the greater tendency to reducing power of metal. K has greater value `( - 2. 93)` so `K gt Mg gt Cr gtAg` . |
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