Given that ᴱ⁰O₂/H₂O = +1.23V; ᴱ⁰S₂O₈²⁻/SO₄²⁻ =

1.	Given that ᴱ⁰O₂/H₂O = +1.23V; ᴱ⁰S₂O₈²⁻/SO₄²⁻ = 2.05 V; ᴱ⁰Br₂/Br⁻ = +1.09 V; ᴱ⁰Au³⁺/Au = 1.4V. The strongest oxidizing agent is:(A) O₂(B) S₂O₈²⁻(C) Au³⁺(D) Br₂
Answer» ANSWER: ACCORDING to my KNOWLEDGE the answer is (C)

Given that ᴱ⁰O₂/H₂O = +1.23V; ᴱ⁰S₂O₈²⁻/SO₄²⁻ = 2.05 V; ᴱ⁰Br₂/Br⁻ = +1.09 V; ᴱ⁰Au³⁺/Au = 1.4V. The strongest oxidizing agent is:(A) O₂(B) S₂O₈²⁻(C) Au³⁺(D) Br₂

Answer»

ACCORDING to my KNOWLEDGE the answer is (C)