Given that \( f(x) =\begin{cases}\sqrt{x-1 } & \quad \text{} x≥1 \t

1.	Given that \( f(x) =\begin{cases}\sqrt{x-1 } & \quad \text{} x≥1 \text{ }\\4 & \quad \text{} x <1\text{ }\end{cases}\)Find(i) f(0) (ii) f(3) (iii) f(a + 1) in terms of a. (Given that a > 0)
Answer» f(x) = \(\sqrt{x-1}\); f(x) = 4 (i) f(0) = 4 (ii) f(3) = \(\sqrt{3-1}\) = \(\sqrt{2}\) (iii) f(a + 1) = \(\sqrt{a+1-1}\) = \(\sqrt{a}\)

Given that \( f(x) =\begin{cases}\sqrt{x-1 } & \quad \text{} x≥1 \text{ }\\4 & \quad \text{} x <1\text{ }\end{cases}\)Find(i) f(0) (ii) f(3) (iii) f(a + 1) in terms of a. (Given that a > 0)

Answer»

f(x) = \(\sqrt{x-1}\); f(x) = 4

(i) f(0) = 4

(ii) f(3) = \(\sqrt{3-1}\) = \(\sqrt{2}\)

(iii) f(a + 1) = \(\sqrt{a+1-1}\) = \(\sqrt{a}\)