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Given that N_2(g)+3H_2(g)rarr2NH_3 Delta_rHtheta=-92.4 What is the sandard enthalpy of formation of NH_3 gas? |
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Answer» SOLUTION :`DeltaH^0` for the FORMATION of 2 moles of `NH_3` from its ELEMENTS=-92.4 KJ`therefore` `DeltaH^0` for the formation of 1 mole of `NH_3` from its elements (i.e. standard enthalpy of fromation of `NH_3`=92.4/2=-46.2 kJ mol^-1` |
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