Given that : (R)CO3+ + e- → CO2+ E˚ = 1.82 V2H2O → O2 + 4H+ + 4 e

1.	Given that : (R)CO3+ + e- → CO2+ E˚ = 1.82 V2H2O → O2 + 4H+ + 4 e- E˚ = -1.23 V Explain why CO3+ is not stable in aqueous solution?
Answer» The E˚ cell can be calculated as : 4[CO³⁺ + e^-→ CO²⁺] E˚= 1.82 V 2H₂O → O₂ + 4H⁺ + 4e^- E˚= -1.23 V Cell reaction : 4CO³⁺ + 2H₂O → CO²⁺O₂ + 4H⁺ E˚ cell = 1.82 V-(-1.23 V) = 3.05 V Since E˚_cell is positive, the cell reaction is spontaneous. CO³⁺ iron will take part in the reaction and hence

Given that : (R)CO3+ + e- → CO2+ E˚ = 1.82 V2H2O → O2 + 4H+ + 4 e- E˚ = -1.23 V Explain why CO3+ is not stable in aqueous solution?

Answer»

The E˚ cell can be calculated as :

4[CO³⁺ + e^-→ CO²⁺] E˚= 1.82 V

2H₂O → O₂ + 4H⁺ + 4e^- E˚= -1.23 V

Cell reaction :

4CO³⁺ + 2H₂O → CO²⁺O₂ + 4H⁺

E˚ cell = 1.82 V-(-1.23 V) = 3.05 V

Since E˚_cell is positive, the cell reaction is spontaneous. CO³⁺ iron will take part in the reaction and hence

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Given that : (R)CO3+ + e- → CO2+ E˚ = 1.82 V2H2O → O2 + 4H+ + 4 e- E˚ = -1.23 V Explain why CO3+ is not stable in aqueous solution?

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