Given that:S∘H2=131 JK−1mol−1S∘Cl2=223 JK−1mol−1and S∘HCl=187 JK−1mol−1The standard entropy change in formation of 1 mole of HCl(g) from H2(g) and Cl2(g) will be:(Given, reaction for formation of HCl : H2+Cl2→2HCl)

Given that:S∘H2=131 JK−1mol−1S∘Cl2=223 JK−1mol−1and S∘HC

1.	Given that:S∘H2=131 JK−1mol−1S∘Cl2=223 JK−1mol−1and S∘HCl=187 JK−1mol−1The standard entropy change in formation of 1 mole of HCl(g) from H2(g) and Cl2(g) will be:(Given, reaction for formation of HCl : H2+Cl2→2HCl)
Answer» Given that: $S_{H_{2}}^{\circ} = 131 J K^{- 1} m o l^{- 1} S_{C l_{2}}^{\circ} = 223 J K^{- 1} m o l^{- 1} a n d S_{H C l}^{\circ} = 187 J K^{- 1} m o l^{- 1}$ The standard entropy change in formation of $1$ mole of $H C l (g)$ from $H_{2} (g)$ and $C l_{2} (g)$ will be: (Given, reaction for formation of $H C l$ : $H_{2} + C l_{2} \to 2 H C l$ )