1.

Given that the solubility product of radium sulphate (RaSO_(4)) is 4xx10^(-11). Calculate the solubility in (a) pure water (b) 0.10 M Na_(2)SO_(4).

Answer»


SOLUTION :`RaSO_(4) hArr Ra^(+) + SO_(4)^(2-) `, In water, `s=sqrt(K_(sp))`. In `Na_(2)SO_(4) ` solution `[Ra^(2+)][0.1]=K_(sp)=4XX10^(-11)`.


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