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Given that the sum of two non-negative quantities is 200, the probability that their product is not less than `3//4` times their greatest product value isA. `7//16`B. `8//16`C. `9//16`D. `10//16` |
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Answer» Correct Answer - B Let x and y be the two quantities. When the sum of two non-negative quantities is fixed, the product will be maximum when they are equal. So, the greatest product =xy=1000 when x=y=100 Now, `xy lt (3)/(4)xx10000` `implies xy ge (3)/(4)xx10000` `implies xy ge 7500` `implies x(200-x) ge 7500` `implies x^(2)-200 x + 7500 le 0` `implies (x-50)(x-150) le 0 implies 50 le x le 150` `therefore` Favourable number of elementary events =101 Total number of elementary events =200. Hence, required probability `=(101)/(200)` |
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