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| 1. |
Given the electronic configurations of the ions : (i) H^(-1) (ii) Na^(+) (iii) N^(-1) (iv) N^(2+) |
| Answer» Solution :(i) `1S^(2)` (ii) `1s^(2) 2s^(2) 2p^(6)` (iii) `1s^(2) 2s^(2) 2p^(4)` (iv) `1s^(2) 2s^(2) 2p^(1)` | |