Given the following cell at `25^(@)C` What will be the potential of the cell ? Given `pK_(a) ` of `CH_(3)COOH=4.74`A. `-0.42V`B. `0.42V`C. `-0.19V`D. `0.19V`

Given the following cell at `25^(@)C` What will be the potential of t

1.	Given the following cell at `25^(@)C` What will be the potential of the cell ? Given `pK_(a) ` of `CH_(3)COOH=4.74`A. `-0.42V`B. `0.42V`C. `-0.19V`D. `0.19V`
Answer» Correct Answer - a It is a concentration cell, therefore, `E^(c-)._(cell)=0` `pH of W_(A)=(1)/(2)(pK_(a)-log c)` `=(1)/(2)(4.74-log 10^(-3))=3.87` `pH of NaOH=14-3=11` `:. E=-0.059(pH_(c)-pH_(a))` `=-0.059(11-3.87)=-0.42V`

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Given the following cell at `25^(@)C` What will be the potential of the cell ? Given `pK_(a) ` of `CH_(3)COOH=4.74`A. `-0.42V`B. `0.42V`C. `-0.19V`D. `0.19V`

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