Given the four lines with the equations `x+2y -3 = 0,3x+4y-7=0, 2x +3y

1.	Given the four lines with the equations `x+2y -3 = 0,3x+4y-7=0, 2x +3y - 4 = 0, 4x+5y -6 =0, then
Answer» Here, we are given 4 lines `x+2y-3=0` `3x+4y-7=0` `2x+3y-4=0` `4x+5y-6=0` If, we subtract twice of third equation from fourth equation, we get `y=2` and putting it in any of the equation, we get `x=-1`. If we put these value in first line equation, `-1+2(2)-3=0` that is ` true`. If we put these value in second line equation, `2(-1)+3(2)-4=0` that is not true. That means three lines are intersecting at point(-1,2), but the fourth one is not that concludes They are not concurrent and they are not forming quardilateral.So, option `C` None of these is the correct option.

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Given the four lines with the equations `x+2y -3 = 0,3x+4y-7=0, 2x +3y - 4 = 0, 4x+5y -6 =0, then

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