Saved Bookmarks
| 1. |
Given the reaction between 3 gases represented `X_(2),Y_(2),Z_(2)` to give the compound `XYZ_((g))` `X_(2(g))+Y_(2(g))+Z_(2(g))hArr 2XYZ_((g))` At equilibrium concentration of `X_(2)=3M, Y_(2)=6M, Z_(2)=9MXYZ=6M` If the reaction takes place in a sealed vessel at `527^(@)C`, then the value of`K_(C)` will be :A. `(27)/(2)`B. `(2)/(9)`C. 36D. 24 |
|
Answer» Correct Answer - B `K_(C)=((6)^(2))/(3xx6xx9)=(6)/(27)=(2)/(9)` |
|