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Given the relation between enthalpy (H) and internal energy (U). |
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Answer» Solution :H = U + PV Considering the initial and FINAL STATES of H U and V as `H_(1) , U_(1) and V_(1) and H_(2) , U_(2) and V_(2) ` CHANGE in ENTHALPY is `(H_(2)-H_(1)) = (U_(2)-U_(1)) +P(V_(2)-V_(1)) ` `Deltah = DeltaU+PDeltaV` |
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