Given the standard electrode potentials K^+//K= -2.93V, Ag^+//Ag = +0.8V, Hg^(2+)//Hg= 0.79 V, Mg^(2+)//Mg = -2.36V Cr^(3+)//Cr = 0.74 V Arrange them in increasing order of reducing power.

Given the standard electrode potentials K^+//K= -2.93V, Ag^+//Ag = +0

1.	Given the standard electrode potentials K^+//K= -2.93V, Ag^+//Ag = +0.8V, Hg^(2+)//Hg= 0.79 V, Mg^(2+)//Mg = -2.36V Cr^(3+)//Cr = 0.74 V Arrange them in increasing order of reducing power.
Answer» SOLUTION :Lower the electrode POTENTIAL, BETTER is the reducing POWER. Hence the reducing power decreases in the order `KgtMg gtCrgtHg GTAG`