Given the standard electrods potential `K^(+)//K=-3.02V` `Cu^(+2)//Hg=+0.34V` `Hg^(+2)//Hg=0.92` `Cr^(+3)//Cr=-0.74V` Decreasing order of reducing power of these element isA. `agtbgtcgtd`B. `agtdgtcgtb`C. `agtdgtbgtc`D. `cgtbgtdgta`

Given the standard electrods potential `K^(+)//K=-3.02V` `Cu^(+2)//Hg=

1.	Given the standard electrods potential `K^(+)//K=-3.02V` `Cu^(+2)//Hg=+0.34V` `Hg^(+2)//Hg=0.92` `Cr^(+3)//Cr=-0.74V` Decreasing order of reducing power of these element isA. `agtbgtcgtd`B. `agtdgtcgtb`C. `agtdgtbgtc`D. `cgtbgtdgta`
Answer» Correct Answer - C

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Given the standard electrods potential `K^(+)//K=-3.02V` `Cu^(+2)//Hg=+0.34V` `Hg^(+2)//Hg=0.92` `Cr^(+3)//Cr=-0.74V` Decreasing order of reducing power of these element isA. `agtbgtcgtd`B. `agtdgtcgtb`C. `agtdgtbgtc`D. `cgtbgtdgta`

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