Saved Bookmarks
| 1. |
Given the unit of power as 1 million erg/ min, the unit of force as 1000 dynes, unit of time as 1/10 s, what is the unit of mass and length. |
|
Answer» Solution :Power `=[ML^(2)T^(-3)]=10^(6)("erg")/("minute")=(10^(6))/60("erg")/s`….i force `=[MLT^(-2)]=10^(3)` dyne ……II Time `=[T]=1/10s`……iii Dividing (i) by (ii) we get `([M L^(2)T^(-3)])/([MLT^(-2)])=(10^(6))/60xx1/(10^(3))` `[LT^(-1)]=50/3`.......iv MULTIPLYING equation (iv) and (iii) we get `[LT^(-1)xxT]=50/3xx1/10` `L=5/3cm` Substituting the vaues of L and T in equation (ii) `Mxx5/3xx100=10^(3),M=1000xx3/5xx1/100` `M=6g` |
|