1.

Given the unit of power as 1 million erg/ min, the unit of force as 1000 dynes, unit of time as 1/10 s, what is the unit of mass and length.

Answer»

Solution :Power `=[ML^(2)T^(-3)]=10^(6)("erg")/("minute")=(10^(6))/60("erg")/s`….i
force `=[MLT^(-2)]=10^(3)` dyne ……II
Time `=[T]=1/10s`……iii
Dividing (i) by (ii) we get
`([M L^(2)T^(-3)])/([MLT^(-2)])=(10^(6))/60xx1/(10^(3))`
`[LT^(-1)]=50/3`.......iv
MULTIPLYING equation (iv) and (iii) we get
`[LT^(-1)xxT]=50/3xx1/10`
`L=5/3cm`
Substituting the vaues of L and T in equation (ii)
`Mxx5/3xx100=10^(3),M=1000xx3/5xx1/100`
`M=6g`


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