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Given these standards reduction potentials, what is the free energy change (in kJ. Mol^(-) for the reaction: `Pb(s) + 2Ag^(+)(aq) rightarrow Pb^(2+)(aq) + 2Ag(s)` `Ag^(+)(aq) + e^(-) rightarrow Ag(s)` `E^(@) = 0.80V` `Pb^(2+)(aq) + 2e^(-) rightarrow Pb(s)` `E^(@) = -0.13V`A. -180B. -90C. 90D. 180 |
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Answer» Correct Answer - A |
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