Given, vecomega=2hatkandvecr=2hati+2hatj. Find the linear velocity.

1.	Given, vecomega=2hatkandvecr=2hati+2hatj. Find the linear velocity.
Answer» `4hati+4hatj` `4hati+4hatk` `-4hati+4hatj` `-4hati-4hatj` Solution :Linear velocity of body of rigid body at distance from the AXIS of body is : `VECV=vecomegaxxvecr` `therefore vecv=(2HATK)xx(2hati+2hatj)` `=(2hatkxx2hati)+(2hatkxx2hatj)` `=4hatj+(-4hatj)(because hatkxxhati=hatj,hatkxxhatj=-hati)` `therefore vecv=-4hatixx4hatj`

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