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Given, `y=sin 2x` . Then find `(dy)/(dx)` . |
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Answer» `(dy)/(dx)=(d)/(dx) (sin 2x)` `=(d(sin u))/(du)xx(du)/(dx)` Here , u=2x `:. " " (du)/(dx)=(d(2x))/(dx)=2 "and " (d(sin u))/(du)=cos u` `:. " " (dy)/(dx) =cos u xx2 ` `=2 cos 2x ` Or `(dy)/(dx)=(d)/(dx)(sin 2x)` `=(d)/(d(2x)) sin (2x) xx (d(2x))/(dx)` ` cos 2x xx 2 = cos 2x` |
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