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Givethe expressionsfor linear,areaandvolumethermal expansions. |
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Answer» Solution :Linear Expansion : In solids, for a SMALL change is temperature `DeltaT`, the fractional change in length `((DeltaL)/(L_(0)))` is DIRECTLY proportional to `DeltaT`. `(DeltaL)/(L_(0))=alpha_(L)DeltaT` `"Therefore,"alpha_(L)=(DeltaL)/(L_(0)DeltaT)` AREA Expansion : For a small change in temperature `DetlaT` the fractional change in area `((DeltaA)/(A_(0)))` of a substance is directly proportional to `DeltaT` and it can be WRITTEN as `(DeltaA)/(A_(0))=alpha_(A)DeltaT` `"Therefore,"alpha_(A)=(DeltaA)/(A_(0)DeltaT)` Volume Expansion : For a small change in temperature `DeltaT` the fractional change in volume `((DeltaV)/(V_(0)))` of a substance is directly proportional to `DeltaT`. `((DeltaV)/(V_(0)))=alpha_(0)DeltaT` `"Therefore,"alpha_(V)=(DeltaV)/(V_(0)DeltaT)` |
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