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Glucose is added to `1` litre water to such an extent that `(Delta T_(f))/(K_(f))` becomes equal to `(1)/(1000)`, the weight of glucose added is:A. (a) `0.32 g`B. (b) `0.42 g`C. ( c) `0.22 g`D. (d) `0.18 g` |
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Answer» Correct Answer - D `Delta T_(f) = K_(f) xx "molality" = K_(f) xx (w xx 1000)/(m xx W)` `:. (Delta T_(f))/(K_(f)) = (w xx 1000)/(m xx W)` or `(1)/(1000) = (w xx 1000)/(180 xx 1000)` `:. w = 0.18 g` |
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