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Glucose is added to `1` litre water to such an extent that `(Delta T_(f))/(K_(f))` becomes equal to `(1)/(1000)`, the weight of glucose added is: |
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Answer» Correct Answer - D `DeltaT_(f)=K_(f)xx"Molality"=K_(f)xx(wxx1000)/(mxxW)` `:.(DeltaT_(f))/(K_(f))=(wxx1000)/(mxxW)` or`(1)/(1000)=(wxx1000)/(180xx1000):.w=0.18g.` |
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