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Glucose when reduced with HI and red phosphorus givesA. n-hexaneB. n-heptaneC. n-pentaneD. n-octane |
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Answer» Correct Answer - A (A) `underset("Glucose")(C_(6)H_(12)O_(6)) overset(HI//Red P)to underset("n-Hexane")(CH_(3)CH_(2)CH_(2)CH_(2)CH_(2)CH_(3))` |
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