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Gold (atomic mass 197 u, atomic radius = 0.144 m ) crystallizes in a face centred unit cell. Determine the density of gold

Answer»

Solution :For fcc unit cell , `r=a/(2sqrt2)` or `a=2sqrt2 r=2xx1.414 XX 0.144`NM = 0.407 nm =`0.407xx10^(-7)` CM
`rho=(ZxxM)/(a^3xxN_0)=(4xx197 "g MOL"^(-1))/((0.407xx10^(-7)cm)^3 xx (6.02xx10^23 mol^(-1)))=19.4 g cm^(-3)`


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