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Gold number of haemoglobin is 0.03. Hence 100 ml of gold sol will require haemoglobin so that gold is not coagulated by 10 ml of 10% NaCl solutionA. 0.03 mgB. 30 mgC. 0.30 mgD. 3mg |
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Answer» Correct Answer - C Gold number=0.03 Gold sol volume =100ml Let the amount of hemoglobin required is x mg Since the gold number is the amount in miligrams required to prevent the coagulation of 10 ml of gold sol by 1 ml of 10% NaCl `therefore(x)/(100)xx10=` gold number `thereforex=0.30mg` |
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