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Graph between log k and `(1)/(T)` (k is rate constant in `s^(-1)` and T is the temperature in K) is a straight line. As shown in figure if OX = 5 and slope of the line `=- (1)/(2.303)`then `E_(a)` is : A. `2.303 xx 2 cal`B. `(2)/(2.303) cal`C. 2 calD. none of these |
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Answer» Correct Answer - C |
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