1.

Graph between log `((x)/(m))` and log p is a straight line at an angle `45^(@)` with intercept on y-axis 0.3010. Calculate the amount of gas adsorbed in gram per gram of the adsorbent when pressure is 0.2 atmA. `0.4`B. `0.6`C. `0.8`D. `0.2`

Answer» Correct Answer - A
`"log"(X)/(M)="log K"+(1)/(n)"log P"`
`Y = C + MX`
intercept (c ) = 0.30
log K = 0.30
`K = 10^(0.3)=2`
`(1)/(n)=tan 45 = 1`
`(1)/(n)=1`
`"log"(X)/(M)=0.30+1xx log 0.2`
`0.30-0.70=-0.40`
`(X)/(M)=10^(-0.40)=10^(-1)xx10^(0.60)=4xx10^(-1)=0.4`


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