Gravitational acceleration on the surface of a planet is √611g where g is the gravitational acceleration on the surface of the earth. The average mass density of the planet is 23 times that of the earth. If the escape speed on the surface of the earth is taken to be 11 kms–1, the escape speed on the surface of the planet in kms–1 will be

Gravitational acceleration on the surface of a planet is √611g wher

1.	Gravitational acceleration on the surface of a planet is √611g where g is the gravitational acceleration on the surface of the earth. The average mass density of the planet is 23 times that of the earth. If the escape speed on the surface of the earth is taken to be 11 kms–1, the escape speed on the surface of the planet in kms–1 will be
Answer» Gravitational acceleration on the surface of a planet is $\frac{\sqrt{6}}{11} g$ where $g$ is the gravitational acceleration on the surface of the earth. The average mass density of the planet is $\frac{2}{3}$ times that of the earth. If the escape speed on the surface of the earth is taken to be $11 k m s^{- 1}$ , the escape speed on the surface of the planet in $k m s^{- 1}$ will be

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