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gThe maximum number of molecules is present in5 L of H2 gas at S.T.PC) 0.5 g of H2 gasB) 5 L of N2 gas at S.T.P.D) 10 g of O2 gas

Answer»

1 mole of H2 has volume → 22.4 L so, in 15L → moles = 15/22.4 = 0.67 mol

similarly for 5L , mole → 5/22.4 = 0.22 mol

0.5g H2 has mole = 0.5/2 = 0.25 mol and 10g Of O2 has mol = 10/32 = 0.33

so, option A



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