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Gunpowder contains 75% nitre and 10% sulphur. Find the amount of the gunpowder which carries 9 kg nitre. What amount of gunpowder would contain 2.3 kg sulphur? |
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Answer» Amount of nitre in gunpowder = 9 kg Percentage of nitre in gunpowder = 75% Let amount of gunpowder = x kg So, \(=\frac{X\times75}{100}\) = 9 \(= {X} =\frac{9\times100}{75}\) = 12 kg Amount of sulphur in gunpowder = 2.3 kg Percentage of sulphur in gunpowder = 10% Let amount of gunpoder = x kg So, \(=\frac{X\times10}{100}\) = 2.3 \(={X} =\frac{2.3\times100}{10}\) = 23 kg |
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