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| Answer» <html><body><p><strong>Explanation:</strong></p><p></p><p>3. 2+√3/2-√3 = 2+√3/2-√3 × 2+√3/2+√3</p><p>= (2+√3)²/(2)²-(√3)² = 4+3+4√3/4-3</p><p>= 7+4√3/1 = 7+4√3</p><p></p><p>4.i)Let ABCD be a trapezium with,</p><p>AB∥CD</p><p>AB=25m</p><p>CD=10m</p><p>BC=14m</p><p>AD=13m</p><p></p><p>Draw CE∥DA. So, <a href="https://interviewquestions.tuteehub.com/tag/adce-1961144" style="font-weight:bold;" target="_blank" title="Click to know more about ADCE">ADCE</a> is a parallelogram with,</p><p>CD=AE=10m</p><p>CE=AD=13m</p><p>BE=AB−AE=25−10=15m</p><p></p><p>In ΔBCE, the semi perimeter will be,</p><p>s= a+b+c/2</p><p>s=14+13+15/2</p><p>s=21m</p><p></p><p><a href="https://interviewquestions.tuteehub.com/tag/area-13372" style="font-weight:bold;" target="_blank" title="Click to know more about AREA">AREA</a> of ΔBCE,</p><p>A=√s(s-a)(s-b)(s-c)</p><p> =√21(21-14)(21-13)(21-15)</p><p> =√21(7)(<a href="https://interviewquestions.tuteehub.com/tag/8-336412" style="font-weight:bold;" target="_blank" title="Click to know more about 8">8</a>)(6)</p><p> =√7056</p><p> =84m²</p><p></p><p>Area of ΔBCE is,</p><p>A=1/2 × <a href="https://interviewquestions.tuteehub.com/tag/base-892693" style="font-weight:bold;" target="_blank" title="Click to know more about BASE">BASE</a> × height</p><p>84=1/2×15×CL</p><p>CL=56/5m</p><p></p><p>Are of trapezium</p><p>A=1/2×(25+10)(56/5)</p><p>A = 196m²</p><p></p><p>Hence,the area of the trapezium is 196m²</p><p></p><p>ii)4:1</p><p></p><p>Hope it helps</p></body></html> | |