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Answer» Explanation: 3. 2+√3/2-√3 = 2+√3/2-√3 × 2+√3/2+√3 = (2+√3)²/(2)²-(√3)² = 4+3+4√3/4-3 = 7+4√3/1 = 7+4√3 4.i)Let ABCD be a trapezium with, AB∥CD AB=25m CD=10m BC=14m AD=13m Draw CE∥DA. So, ADCE is a parallelogram with, CD=AE=10m CE=AD=13m BE=AB−AE=25−10=15m In ΔBCE, the semi perimeter will be, s= a+b+c/2 s=14+13+15/2 s=21m AREA of ΔBCE, A=√s(s-a)(s-b)(s-c) =√21(21-14)(21-13)(21-15) =√21(7)(8)(6) =√7056 =84m² Area of ΔBCE is, A=1/2 × BASE × height 84=1/2×15×CL CL=56/5m Are of trapezium A=1/2×(25+10)(56/5) A = 196m² Hence,the area of the trapezium is 196m² ii)4:1 Hope it helps |
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