InterviewSolution
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InterviewSolution
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Guys Please help me......... |
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Answer» 1Explanation:2) We have,f(X) = x2-√2x -12Now, put f(x) = 0X2-√2x –12 = 0x2 - 3√2x + 2√2x – 12 = 0x(x - 3√2) + 2√2(x - 3√2) = 0(x - 3√2)(x + 2√2) = 0x - 3√2 = 0 or x + 2√2 = 0x = 3√2 or x = -2√2So, the ZEROS of given polynomial are 3√2 and -2√2. |
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