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H_(2)(g) + (1)/(2)O_(2)(g) rarr H_(2)O(g) Delta H = -242 kJ mol^(-1). Bond energy of H_(2) and O_(2) are 436 mol^(-1) and 500 mol^(-1) respectively. What is the bond energy of the O-H bond ? |
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Answer» Solution :`H_(2)(g) + (1)/(2)O_(2)(g) RARR H_(2)O(g) , Delta_(F)H^(@) = -242 kJ mol^(-1)` H = Bond energy of reaction - Bond energy of products `Delta H = B_(H-H) + (1)/(2)B_(O-O) - 2B_(O-H) , -242 kJ = 436 + (1)/(2)(500) - 2B_(O-H) hArr -928 kJ = -2B_(O-H), B_(O-H) = (928)/(2) = 464 kJ mol^(-1)`. |
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