H_(2(g)) + I_(2(g)) hArr 2HI_((g)) for this reaction K_c=[HI]^2/([H_2][I_2])=9 what is the equilibriumconstant for reverse reaction ?

H_(2(g)) + I_(2(g)) hArr 2HI_((g)) for this reaction K_c=[HI]^2/([H_2]

1.	H_(2(g)) + I_(2(g)) hArr 2HI_((g)) for this reaction K_c=[HI]^2/([H_2][I_2])=9 what is the equilibriumconstant for reverse reaction ?
Answer» Solution :Reverse reaction `2HI_((G)) HARR H_(2(g)) + I_(2(g))` `K._c=([H_2][I_2])/[HI]^2=1/K_c=1/9`